題目如下：
Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
我之前拿這題來當好多語言入門的練習題啊～
class Solution(object):
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
for i in range(len(nums)-1):
for j in range(i+1, len(nums)):
if nums[i] + nums[j] == target:
return [i, j]
public class Solution {
public int[] TwoSum(int[] nums, int target) {
for(int i = 0; i<nums.Length; i++)
{
for(int j = i+1; j<nums.Length; j++)
{
if (nums[i] + nums[j] == target)
return new int[] {i,j};
}
}
return null;
}
}
func twoSum(nums []int, target int) []int {
m := make(map[int]int)
for i := 0; i < len(nums); i++ {
k := target - nums[i]
v, ok := m[k]
if ok {
return []int{i, v}
} else {
m[nums[i]] = i
}
}
return nil
}